方法不唯一哟~~~

$so$ $easy$

代码：

#include <bits/stdc++.h>
using namespace std;
int a[15];
double sum;
int main(){
	for(int i=1;i<=10;i++){
        cin>>a[i];
        switch(i){
            case 1:
                sum+=a[i]*28.9;
                break;
            case 2:
                sum+=a[i]*32.7;
                break;
            case 3:
                sum+=a[i]*45.6;
                break;
            case 4:
                sum+=a[i]*78;
                break;
            case 5:
                sum+=a[i]*35;
                break;
            case 6:
                sum+=a[i]*86.2;
                break;
            case 7:
                sum+=a[i]*27.8;
                break;
            case 8:
                sum+=a[i]*43;
                break;
            case 9:
                sum+=a[i]*56;
                break;
            case 10:
                sum+=a[i]*65;
                break;
        }
    }
    printf("%0.1lf",sum);
}